Some phones support the hardware back button and this may disturb the designed navigation experience that has been implemented in the application. You can override this behavior on Android (iOS does not support a hardware back button) with the following code that has to be placed in the MainActivity.cs of your Android root folder after onCreate method.
The result should look like below. After this action the hardware back button will have no effect and the whole navigation can be performed through the application.
The Fibonacci sequence begins with Fibonacci(0) = 0 and Fibonacci(1)=1 as its respective first and second terms. After these first two elements, each subsequent element is equal to the sum of the previous two elements.
Here is the basic information you need to calculate Fibonacci(n):
Fibonacci(0) = 0
Fibonacci(1) = 1
Fibonacci(n) = Fibonacci(n-1) + Fibonacci(n-2)
Given n, complete the fibonacci function so it returns Fibonacci(n).
Fibonacci() Nth number.
Consider the Fibonacci sequence:
We want to know the value of Fibonacci(3). If we look at the sequence above,Fibonacci(3) evaluates to 2. Thus, we print 2 as our answer.
A left rotation operation on an array of size n shifts each of the array’s elements 1 unit to the left. For example, if 2 left rotations are performed on array [1,2,3,4,5], then the array would become [3,4,5,1,2].
Given an array of n integers and a number, d , perform d left rotations on the array. Then print the updated array as a single line of space-separated integers.
The first line contains two space-separated integers denoting the respective values of (the number of integers) and (the number of left rotations you must perform).
The second line contains space-separated integers describing the respective elements of the array’s initial state.
Print a single line of space-separated integers denoting the final state of the array after performing left rotations.
Rotate Array by D
We can see the results for 1 and 4 rotations as follows: